20/7=5/7(m^2)+3m

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Solution for 20/7=5/7(m^2)+3m equation: 


m in (-oo:+oo)

20/7 = (5/7)*m^2+3*m // - (5/7)*m^2+3*m

20/7-((5/7)*m^2)-(3*m) = 0

(-5/7)*m^2-3*m+20/7 = 0

20/7-5/7*m^2-3*m = 0

DELTA = (-3)^2-(-5/7*20/7*4)

DELTA = 841/49

DELTA > 0

m = ((841/49)^(1/2)+3)/(-5/7*2) or m = (3-(841/49)^(1/2))/(-5/7*2)

m = -5 or m = 4/5

m in { -5, 4/5 }

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